Reckoning (opens in new tab)
A problem from the October 1961 issue of Eureka, the journal of the Cambridge University Mathematical Society: When A was three times as old as B was the year before A was a half of B’s present age, B was 3 years younger than A was when B was two thirds of A’s present age. A’s and B’s ages now total 73. How old are A and B?
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