Dice pervert question: how would you use two eight-sided dice to choose between four outcomes with 31:31:1:1 odds? I can find several ways to do it, but none fe... (opens in new tab)

Assuming we're talking about two identical dice (i.e., so no goofy tricks like comparing the values of two different-coloured dice, d88 lookup tables, etc.), if I needed that exact distribution, my inclination would be not to overthink it; take the sum of the dice, with result A (1/64) on 2, result B (31/64) on 3–8, result C (31/64) on 10-15, and result D (1/64) on 16. On a sum of exactly 9, use some sort of 50/50 tie-breaker (e.g., a coin flip) to decide between B and C.(You could dispense w...