You’re wandering through a forest, and spot a binary operator \star.
(a, b) \star (c, d) = (a + c, b + d)
"Cute," you say, "it’s just vector addition."
It retreats into a bush.
"Gone but not forgotten," you murmer as you scribble notes in the sand.
- \vec{x} = (a, b)
- \vec{y} = (c, d)
Maybe \star is the simpliest binary operator you know. After all, it obeys all the pleasing properties you could possibly imagine.
- The lovely symmetry, \vec{x} \star \vec{y} = \vec{y} \star \vec{x}
- The forgiving order of operations, \big(\vec{x} \star \vec{y}) \star \vec{z} = \vec{x} \star \big(\vec{y} \star \vec{z}\big)
- The unimposing zero, \vec{x} \star \vec{0} = \vec{x}
- The inverted twin, \vec{x} \star -\vec{x} = \vec{0}
The s…
You’re wandering through a forest, and spot a binary operator \star.
(a, b) \star (c, d) = (a + c, b + d)
"Cute," you say, "it’s just vector addition."
It retreats into a bush.
"Gone but not forgotten," you murmer as you scribble notes in the sand.
- \vec{x} = (a, b)
- \vec{y} = (c, d)
Maybe \star is the simpliest binary operator you know. After all, it obeys all the pleasing properties you could possibly imagine.
- The lovely symmetry, \vec{x} \star \vec{y} = \vec{y} \star \vec{x}
- The forgiving order of operations, \big(\vec{x} \star \vec{y}) \star \vec{z} = \vec{x} \star \big(\vec{y} \star \vec{z}\big)
- The unimposing zero, \vec{x} \star \vec{0} = \vec{x}
- The inverted twin, \vec{x} \star -\vec{x} = \vec{0}
The sound of something else familiar catches your eye.
(a, b) \star_2 (c, d) = (ad + bc, bd)
"Funny little thing, aren’t you?"
You find comfort in what \star_2 does to the second terms. It simply multiplies them, bd.
"I know you."
You realize it’s nothing more than adding fractions \frac{a}{b} and \frac{c}{d}.
As the sky darkens, mysterious creatures wander closer.
(a, b) \star_3 (c, d) = (ac - bd, ad + bc)
There’s no way you recognize it.
This is the process of multiplying complex numbers a + bi and c + di.
"How peculiar, " you say, "I would have never guessed."
As you look at the next beast ahead, you shout, "this has got to be nonsense."
(a, b) \star_4 (c, d) = (ac + 2bd, ad + bc)
What you see is the multiplication of numbers of the form a + b \sqrt{2} and c+ d \sqrt{2}.